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Revision as of 16:12, 13 July 2010
- If the text does not represent a number ("abc" for example), parseNumber will return 0 (zero). It is therefore not possible to use parseNumber to determine if the string contains a valid number or not.
I beg to differ.
_stringNotContainingValidNumber = "abc";
if(parseNumber _stringNotContainingValidNumber == 0 && _stringNotContainingValidNumber != "0") then
{
comment "INVALID NUMBER";
}
else
{
comment "VALID NUMBER";
};
MulleDK13 09:26, 11 July 2010 (CEST)