arrayIntersect – Talk
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_secondArray = [1,"b",0,"a"];<br> | _secondArray = [1,"b",0,"a"];<br> | ||
_areEquivalent = _firstArray isEqualTo (_secondArray arrayIntersect _firstArray) // returns true | _areEquivalent = _firstArray isEqualTo (_secondArray arrayIntersect _firstArray) // returns true | ||
Note: _areEquivalent can return true, in some cases, even if the arrays haven't the same size. So, compare sizes before contents. | |||
</dd> | </dd> | ||
</dl> | </dl> | ||
<!-- DISCONTINUE Notes --> | <!-- DISCONTINUE Notes --> | ||
Revision as of 06:28, 18 February 2019
- Posted on December 11, 2018 - 18:09 (UTC)
- Pierre MGI
-
useful to compare two arrays with same (single) elements but in different order:
_areEquivalent = _firstArray isEqualTo (_secondArray arrayIntersect _firstArray);
example:
_fistArray = ["a","b",0,1];
_secondArray = [1,"b",0,"a"];
_areEquivalent = _firstArray isEqualTo (_secondArray arrayIntersect _firstArray) // returns true Note: _areEquivalent can return true, in some cases, even if the arrays haven't the same size. So, compare sizes before contents.