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People use logarithm at the purpose of simplifying multiplication via exponents plus years before.
People use logarithm at the purpose of simplifying multiplication via exponents plus years before.
<code>23456*45634 = 1.07039e+009
<code>23456*45634 = 1.07039e+009
[[log]] 23456 = 4.37025; [[log]] 45634 = 4.65929; ([[log]] 23456) + ([[log]] 45634) = 9.02954
log 23456 = 4.37025; [[log]] 45634 = 4.65929; ([[log]] 23456) + ([[log]] 45634) = 9.02954
10^(([[log]] 23456) + ([[log]] 45634)) = 10 ^ 9.02954  // same as 23456*45634
10^(([[log]] 23456) + ([[log]] 45634)) = 10 ^ 9.02954  // same as 23456*45634</code>
</code>
As modern usage, for instance, to evaluate another exponent when multiple is known (Which magnitude is 4 times stronger than 8.3 earthquake?):
As modern usage, for instance, to evaluate another exponent when multiple is known (Which magnitude is 4 times stronger than 8.3 earthquake?):
<code>//_Unknown = [[log]] x; 8.3 = [[log]] y
<code>//_Unknown = log x; 8.3 = [[log]] y
// x = 10 ^_Unknown; y = 10 ^8.3
// x = 10 ^_Unknown; y = 10 ^8.3
//x/y = (10 ^_Unknown)/(10 ^8.3) = [[log]] 4
//x/y = (10 ^_Unknown)/(10 ^8.3) = [[log]] 4
// x/y = _Unknown – 8.3 = 0.6
// x/y = _Unknown – 8.3 = 0.6
//_result = 8.9 magnitude
//_result = 8.9 magnitude
_result = ([[log]] 4) + 8.3
_result = ([[log]] 4) + 8.3</code>
</code>
</dd>
</dd>


</dl>
</dl>

Revision as of 13:00, 12 May 2022

Hover & click on the images for description

Description

Description:
Base-10 logarithm of x.
The function of log(x) will never touch the y-axis.
Groups:
Math

Syntax

Syntax:
log x
Parameters:
x: Number - A positive number
Return Value:
Number

Examples

Example 1:
_log = log 10;
Example 2:
_log = log abs -10;
Example 3:
finite log -10; // Returns false

Additional Information

See also:
Math Commands, Logarithm

Notes

Report bugs on the Feedback Tracker and/or discuss them on the Arma Discord or on the Forums.
Only post proven facts here! Add Note
Posted on 23:14, 16 Jun 2014
ffur2007slx2_5
To clarify: y = 10 ^ x // x = log y People use logarithm at the purpose of simplifying multiplication via exponents plus years before. 23456*45634 = 1.07039e+009 log 23456 = 4.37025; log 45634 = 4.65929; (log 23456) + (log 45634) = 9.02954 10^((log 23456) + (log 45634)) = 10 ^ 9.02954 // same as 23456*45634 As modern usage, for instance, to evaluate another exponent when multiple is known (Which magnitude is 4 times stronger than 8.3 earthquake?): //_Unknown = log x; 8.3 = log y // x = 10 ^_Unknown; y = 10 ^8.3 //x/y = (10 ^_Unknown)/(10 ^8.3) = log 4 // x/y = _Unknown – 8.3 = 0.6 //_result = 8.9 magnitude _result = (log 4) + 8.3