parseNumber – Talk

• If the text does not represent a number ("abc" for example), parseNumber will return 0 (zero). It is therefore not possible to use parseNumber to determine if the string contains a valid number or not.

I beg to differ.

_stringNotContainingValidNumber = "abc";
if(parseNumber _stringNotContainingValidNumber == 0 && _stringNotContainingValidNumber != "0") then
{
    comment "INVALID NUMBER";
}
else
{
    comment "VALID NUMBER";
};

MulleDK13 09:26, 11 July 2010 (CEST)

Huh?

Those past 3 edits make my head hurt. where did that old note come from? It went, it came, it went again... --Benargee (talk) 00:47, 3 October 2014 (CEST)