log: Difference between revisions

Revision as of 16:24, 16 June 2014

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Example 1:

_log = log 10 ..........Result is 1

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Posted on 23:14, 16 Jun 2014
ffur2007slx2_5: (ArmA3 1.20) To clarify: y = 10 ^ x // x = log y People use logarithm at the purpose of simplifying multiplication via exponents plus years before. 23456*45634 = 1.07039e+009 log 23456 = 4.37025; log 45634 = 4.65929; (log 23456) + (log 45634) = 9.02954 10^((log 23456) + (log 45634)) = 10 ^ 9.02954 // same as 23456*45634 As modern usage, for instance, to evaluate another exponent when multiple is known (Which magnitude is 4 times stronger than 8.3 earthquake?): //_Unknown = log x; 8.3 = log y // x = 10 ^_Unknown; y = 10 ^8.3 //x/y = (10 ^_Unknown)/(10 ^8.3) = log 4 // x/y = _Unknown – 8.3 = 0.6 //_result = 8.9 magnitude _result = (log 4) + 8.3

@@ Line 27: / Line 27: @@
 <dl class="command_description">
 <!-- Note Section BEGIN -->
+<dd class="notedate">Posted on 23:14, 16 Jun 2014</dd>
+<dt class="note">[[User:ffur2007slx2_5|ffur2007slx2_5]]</dt>
+<dd class="note">
+(ArmA3 1.20) To clarify:
+<code>y = 10 ^ x // x = log y</code>
+People use logarithm at the purpose of simplifying multiplication via exponents plus years before.
+<code>23456*45634 = 1.07039e+009
+[[log]] 23456 = 4.37025; [[log]] 45634 = 4.65929; ([[log]] 23456) + ([[log]] 45634) = 9.02954
+^(([[log]] 23456) + ([[log]] 45634)) = 10 ^ 9.02954  // same as 23456*45634
+</code>
+As modern usage, for instance, to evaluate another exponent when multiple is known (Which magnitude is 4 times stronger than 8.3 earthquake?):
+<code>//_Unknown = log x; 8.3 = log y
+// x = 10 ^_Unknown; y = 10 ^8.3
+//x/y = (10 ^_Unknown)/(10 ^8.3) = [[log]] 4
+// x/y = _Unknown – 8.3 = 0.6
+//_result = 8.9 magnitude
+_result = ([[log]] 4) + 8.3
+</code>
+</dd>
 <!-- Note Section END -->
 </dl>