dateToNumber: Difference between revisions

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This is how this command works. The 365 days of the year are presented in range 0...1. So each day will be:<br>
This is how this command works. The 365 days of the year are presented in range 0...1. So each day will be:<br>
<tt>1 / 365 <nowiki>=</nowiki>  0.00273973</tt> <br>
<tt>1 / 365 <nowiki>=</nowiki>  0.00273973</tt> <br>
On leap year there are 366 days, so the range will increase by 1 day:<br>
In a leap year there are 366 days, so the range will increase by 1 day:<br>
<tt>1 / 365  *  366 <nowiki>=</nowiki> 1.00274</tt><br>
<tt>1 / 365  *  366 <nowiki>=</nowiki> 1.00274</tt><br>
In short, on normal year the command returns in range 0...1 on leap year it will return in range 0...1.00274|= Description
In short, on normal year the command returns in range 0...1 in a leap year it will return in range 0...1.00274|= Description
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Revision as of 01:12, 27 February 2016

Hover & click on the images for description

Description

Description:
Convert a date to a float number, based on Jan 1st 00:00:00 = 0 and Dec 31st 23:59:59 = 1. The same day and time in leap year will be different after 28th of February and 23:59 on 31st of December will be 1.00274

This is how this command works. The 365 days of the year are presented in range 0...1. So each day will be:
1 / 365 = 0.00273973
In a leap year there are 366 days, so the range will increase by 1 day:
1 / 365 * 366 = 1.00274
In short, on normal year the command returns in range 0...1 in a leap year it will return in range 0...1.00274
Groups:
Uncategorised

Syntax

Syntax:
dateToNumber date
Parameters:
date: Array - array in date format
Return Value:
Number

Examples

Example 1:
_float = dateToNumber [2035,7,6,12,0]; //0.510959
Example 2:
dateToNumber date; //will return float number for the current date.

Additional Information

See also:
datedaytimetimenumberToDate

Notes

Report bugs on the Feedback Tracker and/or discuss them on the Arma Discord or on the Forums.
Only post proven facts here! Add Note

Notes

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