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|gr1= Environment | |gr1= Environment | ||
|descr= Convert a date to a float number, based on Jan 1st 00:00:00 | |descr= Convert a date to a float number, based on Jan 1st 00:00:00 = 0 and Dec 31st 23:59:59 = 1. The same day and time in leap year will be different after 28th of February and 23:59 on 31st of December will be 1.00274.<br><br> | ||
This is how this command works. The 365 days of the year are presented in range 0...1. So each day will be: | This is how this command works. The 365 days of the year are presented in range 0...1. So each day will be: | ||
< | <sqf>1 / 365 = 0.00273973</sqf> | ||
In a leap year there are 366 days, so the range will increase by 1 day: | In a leap year there are 366 days, so the range will increase by 1 day: | ||
< | <sqf>1 / 365 * 366 = 1.00274</sqf> | ||
In short, in a normal year the command returns in range 0...1 in a leap year it will return in range 0...1.00274 | In short, in a normal year the command returns in range 0...1 in a leap year it will return in range 0...1.00274. | ||
|s1= | |s1= [[dateToNumber]] date | ||
|p1= date: [[Array]] - array in [[date]] format | |p1= date: [[Array]] - array in [[date]] format | ||
| Line 28: | Line 28: | ||
|r1= [[Number]] | |r1= [[Number]] | ||
|x1= < | |x1= <sqf>_float = dateToNumber [2035,7,6,12,0]; // 0.510959</sqf> | ||
|x2= < | |x2= <sqf>dateToNumber date; // returns float number for the current date</sqf> | ||
|x3= Calculate days from 1/1/1970: < | |x3= Calculate days from 1/1/1970: | ||
<sqf> | |||
fnc_daysFromEpoc = | |||
{ | { | ||
private _year = param [0]; | |||
private _days = 0; | |||
for "_i" from 1970 to _year - 1 do | |||
{ | { | ||
_days = _days + | _days = _days + round linearConversion [0, 1, dateToNumber [_i, 12, 31, 23, 59], 0, 365, false]; | ||
}; | }; | ||
_days + | _days + linearConversion [0, 1, dateToNumber _this, 0, 365, false]; | ||
}; | }; | ||
hint str (date call fnc_daysFromEpoc); | |||
</sqf> | |||
|seealso= [[date]] | |seealso= [[date]] [[dayTime]] [[time]] [[numberToDate]] | ||
}} | }} | ||
Latest revision as of 13:12, 13 May 2022
Description
- Description:
- Convert a date to a float number, based on Jan 1st 00:00:00 = 0 and Dec 31st 23:59:59 = 1. The same day and time in leap year will be different after 28th of February and 23:59 on 31st of December will be 1.00274.
This is how this command works. The 365 days of the year are presented in range 0...1. So each day will be: In a leap year there are 366 days, so the range will increase by 1 day: In short, in a normal year the command returns in range 0...1 in a leap year it will return in range 0...1.00274. - Groups:
- Environment
Syntax
- Syntax:
- dateToNumber date
- Parameters:
- date: Array - array in date format
- Return Value:
- Number
Examples
- Example 1:
- Example 2:
- Example 3:
- Calculate days from 1/1/1970:
fnc_daysFromEpoc = { private _year = param [0]; private _days = 0; for "_i" from 1970 to _year - 1 do { _days = _days + round linearConversion [0, 1, dateToNumber [_i, 12, 31, 23, 59], 0, 365, false]; }; _days + linearConversion [0, 1, dateToNumber _this, 0, 365, false]; }; hint str (date call fnc_daysFromEpoc);
Additional Information
- See also:
- date dayTime time numberToDate
Notes
-
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Only post proven facts here! Add Note