parsingNamespace: Difference between revisions

From Bohemia Interactive Community
Jump to navigation Jump to search
No edit summary
No edit summary
Line 58: Line 58:
This example however:
This example however:
<code>__EXEC(_testVar = 1);</code>
<code>__EXEC(_testVar = 1);</code>
Would print 0, because adding an underscore will make the variable local to the config in the same way that it would make it local to a script.
Would print 0, because adding an underscore will make the variable local to the config in the same way that it would make it local to a script.<br/><br/>
See [[PreProcessor Commands]] for more details on __EXEC()
</dd>
</dd>
</dl>
</dl>
<!-- DISCONTINUE Notes -->
<!-- DISCONTINUE Notes -->

Revision as of 19:50, 27 January 2015

Hover & click on the images for description

Description

Description:
Return the global namespace attached to config parser.
Groups:
Uncategorised

Syntax

Syntax:
parsingNamespace
Return Value:
Namespace

Examples

Example 1:
parsingNamespace setVariable ["var1",101.23124]; _profVar1 = parsingNamespace getVariable "var1";

Additional Information

See also:
Forward CompatibilityuiNamespaceprofileNamespacemissionNamespacewith

Notes

Report bugs on the Feedback Tracker and/or discuss them on the Arma Discord or on the Forums.
Only post proven facts here! Add Note

Notes

Bottom Section

Posted on January 27, 2015 - 18:08 (UTC)
BrotherhoodOfHam

Any global variable defined in a config using __EXEC() will be stored in this namespace.
For example in the description.ext:
__EXEC(testVar = 1); The variable "testVar" can be accessed during mission run time using getVariable hint str (parsingNamespace getVariable ["testVar", 0]); The above example would print 1.

This example however: __EXEC(_testVar = 1); Would print 0, because adding an underscore will make the variable local to the config in the same way that it would make it local to a script.

See PreProcessor Commands for more details on __EXEC()