dateToNumber

1.00

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Description

Description:

Convert a date to a float number, based on Jan 1st 00:00:00 = 0 and Dec 31st 23:59:59 = 1. The same day and time in leap year will be different after 28th of February and 23:59 on 31st of December will be 1.00274

This is how this command works. The 365 days of the year are presented in range 0...1. So each day will be:
1 / 365 = 0.00273973
In a leap year there are 366 days, so the range will increase by 1 day:
1 / 365 * 366 = 1.00274
In short, in a normal year the command returns in range 0...1 in a leap year it will return in range 0...1.00274

Groups:

Uncategorised

Syntax

Syntax:

dateToNumber date

Parameters:

date: Array - array in date format

Return Value:

Number

Examples

Example 1:

_float = dateToNumber [2035,7,6,12,0]; //0.510959

Example 2:

dateToNumber date; //will return float number for the current date.

Example 3:

Calculate days from 1/1/1970: fnc_daysFromEpoc = { private _year = param [0]; private _days = 0; for "_i" from 1970 to _year - 1 do { _days = _days + round linearConversion [0, 1, dateToNumber [_i, 12, 31, 23, 59], 0, 365, false]; }; _days + linearConversion [0, 1, dateToNumber _this, 0, 365, false]; }; hint str (date call fnc_daysFromEpoc);

Additional Information

See also:

datedaytimetimenumberToDate

Notes

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