vectorNormalized: Difference between revisions
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<code> | <code> | ||
Vector = [x,y,z]; | Vector = [x,y,z]; | ||
Result = [ | Result = [x/([[sqrt]] (x ^ 2 + y ^ 2 + z ^ 2)), y/([[sqrt]] (x ^ 2 + y ^ 2 + z ^ 2)), z/([[sqrt]] (x ^ 2 + y ^ 2 + z ^ 2))] | ||
</code> | </code> | ||
In mathematics, a unit vector in a normed vector space is a vector whose length is 1. | In mathematics, a unit vector in a normed vector space is a vector whose length is 1. | ||
Revision as of 15:52, 22 August 2014
Description
- Description:
- Returns normalized vector (unit vector, vectorMagnitude = 1) of given vector. If given vector is 0 result is a 0 vector as well.
- Groups:
- Uncategorised
Syntax
Examples
- Example 1:
vectorNormalized [12345,7890,38383]; //[0.300481,0.192045,0.934254] vectorMagnitude [0.300481,0.192045,0.934254]; //1
Additional Information
- See also:
- vectorDiffvectorCrossProductvectorDotProductvectorCosvectorMagnitudevectorMagnitudeSqrvectorMultiplyvectorDistancevectorDistanceSqrvectorDirvectorUpsetVectorDirsetVectorUpsetVectorDirAndUpvectorFromTo
Notes
-
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Notes
- Posted on 19 Jul, 2014
- ffur2007slx2_5
-
(ArmA3 1.26) Algorithm:
Vector = [x,y,z]; Result = [x/(sqrt (x ^ 2 + y ^ 2 + z ^ 2)), y/(sqrt (x ^ 2 + y ^ 2 + z ^ 2)), z/(sqrt (x ^ 2 + y ^ 2 + z ^ 2))]In mathematics, a unit vector in a normed vector space is a vector whose length is 1.