a = b: Difference between revisions

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(Updated my note)
(Added publicVariable as an example to my note.)
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If the assignment operator was a regular operator, ''hello'' would first evaluate to ''[[nil]]'' and finally ''nil &#61; 10'', which wouldn't make a whole lot of sense.<br />
If the assignment operator was a regular operator, ''hello'' would first evaluate to ''[[nil]]'' and finally ''nil &#61; 10'', which wouldn't make a whole lot of sense.<br />
<br />
<br />
To work as a regular operator, and like any other operator requiring a reference to a variable rather than the variable's value (Eg. [[isNil]]), its syntax would have had to be.
To work as a regular operator, and like any other operator requiring a reference to a variable rather than the variable's value (Eg. [[isNil]] and [[publicVariable]]), its syntax would have had to be.
<code>"hello" &#61; 5</code><br />
<code>"hello" &#61; 5</code><br />
</dd>
</dd>
</dl>
</dl>
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Revision as of 19:52, 3 October 2014

Hover & click on the images for description

Description

Description:
Assigns the result of expression b to variable a.
Groups:
Uncategorised

Syntax

Syntax:
a = b
Parameters:
a: Anything
b: Anything
Return Value:
Nothing

Examples

Example 1:
_value = 5 _mygroup = group player _greeting = "Hello!" _enemytank = mytank1

Additional Information

See also:
Operators

Notes

Report bugs on the Feedback Tracker and/or discuss them on the Arma Discord or on the Forums.
Only post proven facts here! Add Note

Notes

Posted on December 15, 2006 - 05:27
Kronzky
A conditional assignment can be done via the following syntax: _msg = if (alive player) then {"you're alive"} else {"you're dead"}
Posted on June 22, 2009 - 16:27
Alef
It's possible to assign to numbers. Numbers values are not changed. Useful instead of assigning to nul or nil when a result is of no use. 0 = [player] execVM "myScript.sqf"

Bottom Section

Posted on October 3, 2014 - 18:38 (UTC)
MulleDK13
The assignment operator is the only operator that isn't really an operator. It is a special construct.
Take for example, the following expression: hello + 5 Assuming hello contained the value 10, hello would evaluate to 10, and 10 + 5 would finally evaluate to 15.

Which is why the assignment operator wouldn't work as a regular operator.
Take for example, the following expression: hello = 10 If the assignment operator was a regular operator, hello would first evaluate to nil and finally nil = 10, which wouldn't make a whole lot of sense.

To work as a regular operator, and like any other operator requiring a reference to a variable rather than the variable's value (Eg. isNil and publicVariable), its syntax would have had to be. "hello" = 5